A 5.42-kg Object Passes Through The Origin At Time t = 0 such That Its X Component Of Velocity Is 5.25 M/s And Its Y Component Of Velocity Is −3.24 M/s. (a) What Is The Kinetic Energy Of The Object At This Time? J (b) At A Later Time T = 2.00 S, the Particle Is Located At X = 8.50 M and Y = 5.00 M. What Constant Force Acted On The Object During This Time Interval? Magnitude = N Direction= ° Measured From The +x Axis (c) What Is The Speed Of The Particle At T = 2.00 S? m/s

A 5.42-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.25 m/s and its y component of velocity is −3.24 m/s. (a) What is the kinetic energy of the object at this time? J (b) At a later time t = 2.00 s, the particle is located at x = 8.50 m and y = 5.00 m. What constant force acted on the object during this time interval? magnitude = N direction= ° measured from the +x axis (c) What is the speed of the particle at t = 2.00 s? m/s

- November 14, 2022 - Edwin Tunner

A 5.42-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.25 m/s and its y component of velocity is −3.24 m/s.

(a) What is the kinetic energy of the object at this time?
J

(b) At a later time t = 2.00 s, the particle is located at x = 8.50 m and y = 5.00 m. What constant force acted on the object during this time interval?

magnitude =	N
direction=	° measured from the +x axis

m/s

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