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## A ball is thrown straight up from a rooftop 160 feet high with an initial velocity of 48 feet per second. The function s(t) = -16t2 + 48t + 160 describes the ball’s height above the ground, s(t), in feet, t seconds after it is thrown.The ball misses the rooftop on its way down and eventually strikes the ground. Solve, What is the instantaneous velocity of the ball 2 seconds after it is thrown?

A ball is thrown straight up from a rooftop 160 feet high with an initial velocity of 48 feet per second. The function s(t) = -16t2 + 48t + 160 describes the ball’s height above the ground, s(t), in feet, t seconds after it is thrown.
The ball misses the rooftop on its way down and eventually strikes the ground. Solve, What is the instantaneous velocity of the ball 2 seconds after it is thrown?

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