Calculate ΔSsurr at 25°C for the following reaction at constant pressure. Will the reaction be spontaneous or non-spontaneous at this temperature? 2 X2 (g) + F2 (g) → 2 FX2 (g) ΔH = +46.6 kJ Group of answer choices ΔSsurr = –46.6 kJ/K; non-spontaneous ΔSsurr = +156 J/K; spontaneous ΔSsurr = +46.6 kJ/K; non-spontaneous ΔSsurr = –156 J/K; non-spontaneous ΔSsurr = –46.6 J/K; spontaneous
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