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## How do I find the density of a hemispherical bowl floating in water? The bowls top is perfectly in line with the water so no water is inside the bowl. The inner radius is r=6cm and the outer radius is R=8cm.

How do I find the density of a hemispherical bowl floating in water? The bowls top is perfectly in line with the water so no water is inside the bowl. The inner radius is r=6cm and the outer radius is R=8cm. (I know the density of water is 1000kg/m^3 and I found the volume of the bowl as V=619.94cm^3 using the formula 2/3*pi*(R-r).) But I am having difficulty after this. I believe I should use the buoyancy formula F=p*g*V but I am not sure. Also, if I do use that formula, if buoyancy formula is equal to the weight of the water displaced, then how do I use that to find the density of the object? Please let me know if I am doing this correctly so far and how I proceed. Also please show me step by step how you solve this because I am still learning Archimedes Principle and such. (sorry for crappy illustration, I am by no means an artist)

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