Let lst = ‘(1 2 3 4 5). The function check-1? returns #t only if the input list contains 1, the function check-2? returns #t only if the input list contains 2, the function check-3? returns #t only if the input list contains 3, and the function check-4? returns #t only if the input list contains 4. What will be the following expression display:
(cond
((check-1? lst) (display ‘1))
((check-2? lst) (display ‘2))
((check-3? lst) (display ‘3))
((check-4? lst) (display ‘4))
(else (display ‘5))
)
a.1234
b.54321
c.15
d.1
e.12345
