Problem 3. (2points) Table below shows results for 10 selected students on Test-1 and Test-2:1234567

Problem 3. (2points) Table below shows results for 10 selected students on Test-1 and Test-2:12345678910 Test-1668578100928055958270 Test-27790709510085701009075 Difference You should use Hypothesis Testing technique to evaluate Null Hypothesis:Ho: there is no significant differences between mean score on Test-1 and Test-2.Use significance level ?= 0.10.Here are steps to follow:a) Calculate difference of scores for each student.b) Find Mean (M) and Sample Standard Deviation (s) for values in the column Difference.c) Find Standard Error of Mean sm = s/?N .d) Calculate t-value as t = M/sme) Use Excel function TDIST(t, df,2) to find p-value (df = N-1).f) Compare p-value with the given significance level 0.10.If p-value is less than 0.10 then reject Ho.If p-value is greater than 0.10 accept Ho.