QUESTION 10The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds wi

QUESTION 10The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pound. A citation catfish should be one of the top 2% in weight. Assume the weights of catfish are normally distributed. Determine the minimum weight (in pounds) to establish the citation designation, but use a Z score of 2, rather than the one you found in the previous problem. If a table is needed for this problem, click on the link to pull it up. Z-Table t-table a.1.6 poundsb.5.264 poundsc.4.8 poundsd.none of the answers givne here.6 points QUESTION 11A simple random sample of size 100 is drawn from a population with a mean of 38 and a standard deviation of 8 and you are interested in the probability ofobtaining a sample mean between 36 and 40. What is/are the Z score(s) that would allow you to find the probability? If a table is needed for this problem, click on the link to pull it up. Z-Table t-table a.none of the answers given here.b.2.5c.-2.5 and 2.5d.-.25 and .25e..25f.-.25g.-2.56 points QUESTION 12A simple random sample is drawn from a population with a mean of 38. What is the probability of obtaining a sample mean between 36 and 40 if the Z scoresassociated with 36 and 40 are -2 and 2 instead of the Z scores you determined for the previous poblem. If a table is needed for this problem, click on the link to pull it up. Z-Table t-table a.none of the answers given here.b..9544c..97725 points QUESTION 13A simple random sample of size 100 is drawn from a population with a mean of 38 and a standard deviation of 8 and your objective is to find the probability of obtaining a sample mean between 36 and 40.To use a z score for the above problem, would it be necessary for the population to be normally distributed?a.no b.yes3 points QUESTION 14If it is known that 55% of the registered voters favor candidate Adams, what is the probability of selecting a simple random sample of 100 voters with the percent in favor of Adams 40% or less?The approximate Z score to find the probability for the above problem is If a table is needed for this problem, click on the link to pull it up. Z-Table t-table a.-4.01b.none of the answers given here.c.3.01d.-3.01e.4.016 points QUESTION 15It is known that 55% of the registered voters favor candidate Adams and you are interested in knowing the probability of selecting a simple random sample of 100 voters with the percent in favor of Adams 40% or less. If the Z score for this problem is -1.5, instead of the one you calculated in the previous problem, waht is this probability? If a table is needed for this problem, click on the link to pull it up. Z-Table t-table a.none of the answers given here.b..9332c..06685 points QUESTION 16A computer printout containing the confidence interval of the mean starting salary determined from a sample of 16 MBA’s selected at random from the most recent graduating class at the Stanford Business School is below Printout 1T Confidence IntervalsVariableNMeanStDevSE Mean95.0 % CIsalary16107188183464586( 97413, 116963)Which of the following is the appropriate interpretation of the above confident interval.a.We are 95% confident that the population mean salary for MBA students from Stanford is between 97413 and 116963.b.We are 95% confident that the proportion of MBA salaries for Stanford graduates is between .097413 and .116963.c.None of the answers given here.d.We are 95% confident that the sample mean salary for the 16 Stanford MBA’s is between 97413 and 116963.5 points QUESTION 17A computer printout containing the confidence interval of the mean starting salary determined from a sample of 16 MBA’s selected at random from the most recent graduating class at the Stanford Business School is below. Printout 1T Confidence IntervalsVariableNMean StDevSE Mean95.0 % CIsalary 16107188183464586( 97413, 116963)For the table above, the appropriate interpretation from a point estimate standpoint isa.The mean salaries for the Stanford MBA graduates is 107188 with 95% confidnce that the maximum error is 9775.b.None of the answers given here.c.The mean salaries for the 16 Stanford MBA graduates is 107188 with 95% confidence that the maximum error in estimating the sample mean is 9775.d.The mean salaries for the 16 Stanford MBA graduates is 107188 with 95% confidence that the maximum error is 4586.e.The mean salaries for the Stanford MBA graduates is 107188 with 95% confidence that the maximum error is 4586.5 points QUESTION 18A computer printout containing the confidence interval of the mean starting salary determined from a sample of 16 MBA’s selected at random from the most recent graduating class at the Stanford Business School is below. Printout 1T Confidence IntervalsVariableNMean StDevSE Mean95.0 % CIsalary 16107188183464586( 97412, 116963)How could one obtain a more accurate estimate in the above problem while maintaining the same level of confidence?a.None of the answers given here.b.By choosing a different t or z valuec.By increasing the sample sized.By decreasing the sample size4 points QUESTION 19A poll is conducted to determine the proportion of the population that will vote for Hillary Clinton in the next election. A computer printout containing the confidence interval estimate of the proportion for a sample of 1000 registered voters is below.SampleXNSample p99.0 % CIZ-ValueP-Value148010000.480000(0.439305, 0.520695)-1.260.206The appropriate interpretation of the confidence interval isa.None of the answers given here.b.We are 99% confident that the proportion of the sample that will vote for Hillary Clinton is between .44 and .52 (in rounded numbers).c.We are 95% confident that the proportion of the population that will vote for Hillary Clinton is between .44 and .52 (in rounded numbers).d.We are 95% confident that the proportion of the sample that will vote for Hillary Clinton is between .44 and .52 (in rounded numbers).e.We are 99% confident that the proportion of the population that will vote for Hillary Clinton is between .44 and .52 (in rounded numbers).5 points QUESTION 20A poll is conducted to determine the proportion of the population that will vote for Hillary Clinton in the next election. A computer printout is below containing the confidence interval estimate of the proportion for a sample of 1000 registered voters.SampleXN Sample p99.0 % CI Z-ValueP-Value148010000.480000(0.439305, 0.520695)-1.260.206Can you can tell if President Bush is behind from the results of the poll?a.Nob.Yes3 points QUESTION 21A consumer research group is surveying the population of New England to estimate the proportion of consumers who use biodegradable laundry detergent. How large a random sample should be drawn if the objective is to estimate the proportion of consumers using biodegradable detergent within .03 error points with 95% confidence?a.17b.1068c.33d.1067e.545