You Have Standardized Your KMnO4 Solution And The Molarity Is 0.1356 M. You Used 10.65 Ml To Reach Equivalence Point With Your Iron Unknown. You Started With 0.7985 G Of Unknown. What Is The % Fe^2+ In Your Unknown? ( Fe^2+ Atomic Wt = 55.847 G/mol, KMnO4 Formula Wt = 158.03 G/mol) 8H^+(aq) + 5Fe^2+(aq) + MnO4^-(aq) --> Mn^2+(aq) + 5Fe^3+(aq) + 4H2O

You have standardized your KMnO4 solution and the molarity is 0.1356 M. You used 10.65 ml to reach equivalence point with your iron unknown. You started with 0.7985 g of unknown. What is the % Fe^2+ in your unknown? ( Fe^2+ atomic wt = 55.847 g/mol, KMnO4 formula wt = 158.03 g/mol) 8H^+(aq) + 5Fe^2+(aq) + MnO4^-(aq) –> Mn^2+(aq) + 5Fe^3+(aq) + 4H2O

- August 19, 2022 - Edwin Tunner

You have standardized your KMnO4 solution and the molarity is 0.1356 M. You used 10.65 ml to reach equivalence point with your iron unknown. You started with 0.7985 g of unknown. What is the % Fe^2+ in your unknown? ( Fe^2+ atomic wt = 55.847 g/mol, KMnO4 formula wt = 158.03 g/mol)

8H^+(aq) + 5Fe^2+(aq) + MnO4^-(aq) –> Mn^2+(aq) + 5Fe^3+(aq) + 4H2O

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